Finite Math Help

[Black Yaris]

Originally Posted by static808

alright, if you wanna actually know the steps that i took, here goes:
1) multiply row 1 by 3, row 2 by -4 and row 3 by 6.
2) row 1 + row 2 = new row 2
3) row 1 + row 3 = new row 3
4) multiply row 1 by -23, row 2 by 3, row 3 by 23.
5) row 1 + row 2 = new row 1
6) row 2 + row 3 = new row 3
7) your 3rd row should now look like: 798z = 1596, OR z = 2.
8) solve backwards from there.

repeat this logic for every problem, and you should be peachy keen. i miss this stuff... but i'll gladly give it up to change diapers and raise my kids right...

--B

life saver that sample should be in our book

[static808]

Originally Posted by Black Yaris

life saver that sample should be in our book

dude, anytime buddy. remember, at the very beginning you can also switch around the equations (1st with the 3rd, 2nd with the 1st, etc...) without affecting the results. why do this?? to get smaller common multiples, so your numbers arent so huge at the end... good luck!

--B

[xed]

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